Sol : ( a + b )³ - a - b = ( a + b )³ - ( a + b ) By taking ( a + b ) as common, = ( a + b ) { ( a + b )² - 1 } = ( a + b ) ( a² + b² + 2 ab - 1 ) [ ( a + b )² = a² + b² + 2 ab ]

5Thank You

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