2s=50m.80m.120m find the area of place. …
CBSE, JEE, NEET, CUET
Question Bank, Mock Tests, Exam Papers
NCERT Solutions, Sample Papers, Notes, Videos
Posted by Jayaraj Bhanu 4 years, 3 months ago
- 1 answers
Related Questions
Posted by Gnani Yogi 2 months, 3 weeks ago
- 0 answers
Posted by Alvin Thomas 2 months, 3 weeks ago
- 0 answers
Posted by Savitha Savitha 2 months, 4 weeks ago
- 0 answers
Posted by T Prudhvi 5 days, 16 hours ago
- 0 answers
Posted by Akhilesh Patidar 2 months, 3 weeks ago
- 0 answers
myCBSEguide
Trusted by 1 Crore+ Students
Test Generator
Create papers online. It's FREE.
CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
Gaurav Seth 4 years, 3 months ago
Question : A triangular park has sides 120 m, 80 m, 50 m. A gardener has to put a fence all around it and also plant grass inside. How much area does he need to plant? Find the cost of fencing it with barbed wire at the rate of Rs 20 per meter leaving a space 3 m wide for a gate on one side.
Answer:
Area to be planted
Cost of the fencing = Rs.4940
Step-by-step explanation:
Given : A triangular park has side 120m ,80m, 50m.
Barbed wire at rate of Rs.20 per meter.
To find : The area of park he need to plant and the cost of fencing leaving a space of 3m wide for a gate on 1 side.
Solution : First we the area by Heron's formula,
Where s is
a= 120m, b=80m, c=50m
Substitute the value,
Now, The area to be planted is
Length of the fenced = Perimeter- space for the gate
Perimeter= a+b+c= 120+80+50=250
Space for the gate is = 3m
Length of the fenced = 250-3 = 247 m
Cost of the fencing = Length of the fence × Wire rate
Cost of the fencing = 247 × 20 = Rs.4940
0Thank You