2sin²x=3cosx
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Posted by Hare Ram Pandit 5 years, 5 months ago
- 3 answers
Gaurav Seth 5 years, 5 months ago
Given Equation is 2sin²x + 3cosx = 0
⇒ 2(1 - cos²x) + 3cosx = 0
⇒ 2 - 2cos²x + 3cosx = 0
⇒ 2cos²x - 3cosx - 2 = 0
⇒ 2cos²x - 4cosx + cosx - 2 = 0
⇒ 2cosx(cosx - 2) + (cosx - 2) = 0
⇒ (2cosx + 1)(cosx - 2) = 0
⇒ cosx - 1/2, cosx = 2[Not possible]
⇒ cosx = -1/2
⇒ x = 120°,240°
⇒ x = (2π/3) + 2πn, x = (4π/3) + 2πn
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Divya Bhardwaj 5 years, 5 months ago
0Thank You