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A tower stands vertically on the ground. From a point on the ground which is 100m away from the foot of the tower, the angle of elevation of the top of a tower is found to be 45°. Find it's height

Posted by Shakthi .Na 5 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Shakthi .Na 5 years, 4 months ago

Draw a right angle triangle which the BC is the adjacent side and AB as a perpendicular side and AC is a hypotenuse Then the given is 45° of angle of elevation so tan A = 45° So, to find the height let AB be the height and BC be the base 100m so, BC/AC = Tan 45° Sub BC and AC and Tan 45° as h and 100 and 1 h/100 = 1 h = 100*1 h= 100

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CBSE > Class 10 > Mathematics