Prove that parallelogram in the same …
CBSE, JEE, NEET, CUET
Question Bank, Mock Tests, Exam Papers
NCERT Solutions, Sample Papers, Notes, Videos
Posted by Pushkar Garg 4 years, 3 months ago
- 1 answers
Related Questions
Posted by Akhilesh Patidar 2 months, 3 weeks ago
- 0 answers
Posted by Alvin Thomas 2 months, 3 weeks ago
- 0 answers
Posted by Savitha Savitha 2 months, 4 weeks ago
- 0 answers
Posted by T Prudhvi 5 days, 22 hours ago
- 0 answers
Posted by Gnani Yogi 2 months, 3 weeks ago
- 0 answers
myCBSEguide
Trusted by 1 Crore+ Students
Test Generator
Create papers online. It's FREE.
CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
Gaurav Seth 4 years, 3 months ago
Let ABCD and EFCD be two parallelograms lying on the same base CD and between the same parallels AF and CD.
We have to prove that area of the parallelograms ABCD and EFCD are equal.
In ADE and BCF,
DAE = CBF (Corresponding angles)
AED = BFC (Corresponding angles)
AD = BC (Opposite sides of the parallelogram ABCD)
ADE BCF (By ASA congruence rule)
We know that congruent figures have the same area.
area (ADE) = area (BCF) … (1)
Now, we have:
area (ABCD) = area(ADE) + area (EDCB)
= area (BCF) + area (EDCB) [Using (1)]
= area (EDCF)
Thus, the areas of the two parallelograms ABCD and EFCD are the same.
1Thank You