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Charge Q flowing through a resistance …

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Charge Q flowing through a resistance R, varies with time t as Q=at-bt^2. Total heat produced in R is...... #iit/jee....

Posted by Khushi....? ??‍? 5 years, 3 months ago

CBSE > Class 12 > Physics

5 answers

Ayush Vishwakarma?? 5 years, 2 months ago

Sorry khushi hm bahut dar jaye the apne padhai se kaise hoga issleye bahut tension me thee. Ye sach hai ki hm kuch din se busy thee pr utna bhi ni ki iss app par na aa paye ...agar aapko bura laga ho to sorry ??.keep learning you are the best. Iss bar tum top kro accha no.lana and not forget ...

Bhargav Rajput? 5 years, 3 months ago

Aree.. its ok?

Khushi....? ??‍? 5 years, 3 months ago

Yes Bhargav you are right....thanks...

Bhargav Rajput? 5 years, 3 months ago

By doing whole cal...(mainly Integration)to cal. Heat produced w.r.t. time its ans is likely to be.[ H=a^3R/6b]??

Mishti ???? 5 years, 3 months ago

Solution- Current I =dQ/dt Therefore if Q=at-bt^2 I = a-2bt Power produced is I^2 × R P = a^2+4b^2 t^2 -4abt If you want to calculate total energy or heat produced you have to integrate P with respect to time t applying the limits from 0 to t. Total energy = a^2×t +4(b^2)(t^3/3)-2ab(t^2)

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