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find two consecutive positive integers,sum of whose squares is 365

Posted by Frederick Francis 5 years, 5 months ago

CBSE > Class 10 > Mathematics

1 answers

Yogita Ingle 5 years, 5 months ago

let the no. be x and x+1
then we have x²+(x+1)²=365
2x²+2x-364=0
x²+x-182=0
x²+14x-13x-182=0
(x+14)(x-13)=0
That gives x=13 Avoiding negative value
one number is 13 and other one 14.

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