Using suitable identities, expand 1.(2x+3y+4z)2
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Yogita Ingle 4 years, 4 months ago
( a + b + c )² = a² + b² + c² + 2ab + 2bc + 2ca .
( 2x +3y + 4z )²
=( 2x )² + ( 3y )² + ( 4z )² + 2(2x)(3y) + 2(3y)(4z) + 2(4z)(2x) .
= 4x² + 9y² + 16z² + 12xy + 24yz + 16zx .
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