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Conceptual question..... 1) Two charges have …

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Conceptual question..... 1) Two charges have radius 12M and magnitude of charge is 5 and the distance b/w them is 10M then find Net force b/w them.???Is it behave like point charge if it is not valid then explain its cause.??
  • 5 answers

Ayush Vishwakarma?? 5 years, 3 months ago

Galat hai bakhlol jake aacha se padho aur ha thumara koi help ni chaiye understand mere question pe kabhi bhi ans mt dena you bloody fool. Question kya hai answer kya deta hai uffff!!!!?.

Vikas Shukla 5 years, 3 months ago

Coulomb's law is applicable on charges that have spherical distribution. Charges that are stationary and charges must not overlap. So upgrade ur knowledge as well ayush vishwakarma besides giving.

Vikas Shukla 5 years, 3 months ago

Okay Mr. Einstein, I agree that I didn't knew it but still u need some manner dude! I was just helping u. Moreover before giving me the tag of foolish u must pay some heed to ur writing skills. One more thing better choose ur words wisely because it is a professional platform not ur mohalla. Use ur mind if u have one. Aur haan apne muh pr Ek dhakan lga kr rkha kro har jagah is tarah Gatar Mat khali kiya kro jo gandgi Tumhare andar bhari h bahar aane lgti h. Samjhe gawar kahin ka! :)

Ayush Vishwakarma?? 5 years, 3 months ago

How you take this formula,this formula only valid for point charge .and i say that magnitude of charge this means charge is always in coulomb.you have no mind foolish.you are wrong not make oversmart jitna puccha jaye utna ka hi ans do faltu baat acchi ni lagti hai understand.

Vikas Shukla 5 years, 3 months ago

U haven't wrote the unit of charge. So I am assuming their magnitude is 5 coulomb also the distance in metre as well as radius. Now by using formula kq1q2/r^2 answer is 2.25*10^9 . No, none of the charge will behave like point charge as u can see that their radius is quite large. Point charges are assumed to be at a single point with no mass, area or volume to avoid forces such as gravitational force and all :)
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