If triangle ABCsimilar to triangle pqr …

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GIVEN: In ∆ABC & ∆PQR, D & S are the mid points of the sides BC & QR . ΔABC ~ ΔPQR AB/PQ = BC/QR = AC/PR ………...(i) [corresponding sides of  two similar triangles are in proportional] Also, ∠A = ∠P, ∠B = ∠Q, ∠C = ∠R …...…(ii) [corresponding angles of two similar triangles are in equal] BD = CD = 1/2 BC  and QS = SR = 1/2QR…….…...(iii) [D is the midpoint of BC and S is the midpoint of QR] AB/PQ = BC/QR   [From eq (i)] AB/PQ = 2BD/2QS [From eq iii ] AB/PQ = BD/QS……………(iv) In ΔABD and ΔPQS, ∠B = ∠Q         [From eq (ii)] AB/PQ = BD/QS [From  eq (iv)] ΔABD ~ ΔPQS (By SAS similarity criterion) AB/PQ = AD/PS [corresponding sides of similar triangles are proportional] Hence, proved. (HOPE THIS WILL HELP YOU )?