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a2x2+3abx+2b2 Find the roots

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a2x2+3abx+2b2 Find the roots

Posted by Mohd Aariq 5 years, 5 months ago

CBSE > Class 10 > Mathematics

1 answers

? Pranali.A.P ? 5 years, 5 months ago

a²x² - 3abx + 2b² = 0 a²x² - 3abx = - 2b² divide each term with a² both sides of the equation , x² - 3bx/a = - 2b²/a² x² - 2 × x × (3b/2a)+(3b/2a)² = ( 3b/2a )² - 2b²/a² ( x - 3b/2a )² = 9b²/4a² - 2b² /a² = ( 9b² - 4b² ) /a² = 5b²/a² x - 3b/2a = ± √ ( 5b²/a² ) x = 3b/2a ± √5 ( b/a ) = [ 3b ± 2√5 b ] / 2a = ( 3 ± 2√5 )b/ 2a (I hope this helps you.)???

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