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Find the value of 3sin^20- 2tan^45+ …

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Find the value of 3sin^20- 2tan^45+ 2sin^70

Posted by Koushik Ch 5 years, 5 months ago

CBSE > Class 10 > Mathematics

2 answers

Ankit Singh 5 years, 5 months ago

3sin²20°-2tan²45°+3sin²70° =3sin²20°-2×(tan45°)²+3{sin(90°×1)-20°}² =3sin²20°-2×(1)²+3cos²20° =3(sin²20°+cos²20°)-2 =3-2 [∵, sin²20°+cos²20°=1] =1 Ans.

1Thank You

Ankit Singh 5 years, 5 months ago

This question is wrong Right question is 3sin^2 20° - 2tan^2 45° + 3sin^2 70°

1Thank You

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CBSE > Class 10 > Mathematics