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Yogita Ingle 4 years, 4 months ago
a² + b² + c² = 83 ------(1)
a + b+ c = 15
On squaring both sides, we get
a² + b² + c² + 2( ab + bc + ca) = 225
=> 83 + 2 ( ab + bc + ca) = 225
=> 2 ( ab + bc + ca) = 142
=> ab + bc + ca = 71 --------(2)
Now,
a³ + b³ + c³- 3abc = ( a +b + c) (a² + b² + c² - ab - bc - ca)
= ( 15) [ 83 - (ab + bc + ca)]
= (15)(83-71)
= 15 × 12
= 180
0Thank You