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In triangle ABC right angle at …

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In triangle ABC right angle at C,find the value of cos(A+B)

    • Posted by Advay Sethia 5 years, 5 months ago

    CBSE > Class 10 > Mathematics
    • 3 answers

    Lucifer?? Morningstar?? 5 years, 5 months ago

    Here in a triangle, given, ✓C=90° angleA+angleB+angleclC=180° . Then, ✓A+✓B=180°-C. => Cos(A+B)= Cos90° => Cos (A+B)=0.

    1Thank You

    Advay Sethia 5 years, 5 months ago

    Plsss plsss write answer in proper way

    0Thank You

    ? Pranali.A.P ? 5 years, 5 months ago

    since ABC is right angled and angle C is 90° therefore, A+B=180° - C A+B=180°-90° A+B= 90° Therefore,cos (A+B)=cos90° =0

    0Thank You

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