Derive Gauss theorem.
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Posted by Shambhavi Raman 5 years, 3 months ago
- 2 answers
Meghna Thapar 5 years, 3 months ago
According to Gauss's theorem the net-outward normal electric flux through any closed surface of any shape is equivalent to 1/ε0 times the total amount of charge contained within that surface. Gauss's Law. The total of the electric flux out of a closed surface is equal to the charge enclosed divided by the permittivity. The electric flux through an area is defined as the electric field multiplied by the area of the surface projected in a plane perpendicular to the field.
Derivation of Gauss's Theorem: Let +q charge is placed at a point O and a point P lies at distance r from the point O. Therefore, the intensity of electric field on the surface at all the points will be equal in magnitude and will be directed radially outward. ∴ The electric flux passing through the spherical surface.
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Shambhavi Raman 5 years, 3 months ago
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