The one zero of the polynomial …

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Yogita Ingle 5 years, 5 months ago
p(x)=x3−6x2+11x−6
p(x)=(x−3)(x2−3x+2)
p(x)=(x−3)(x2−2x−x+2)
p(x)=(x−3)(x−1)(x−2)
(x−1)(x−2)(x−3)=0
x=1,2,3
Thus, the other two zeroes of the polynomial are 1 and 2.
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