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Two pipe running together in 3. …

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Two pipe running together in 3. 1/13 min if one pipe takes 3 min more than the other . To fill the tank, then find the time taken by each pipe to seprate the tank .

Posted by ? Pranali.A.P ? 5 years, 5 months ago

CBSE > Class 10 > Mathematics

4 answers

Lucifer?? Morningstar?? 5 years, 5 months ago

Let faster pipe takes x min to fill the cistern. To fill the cistern slower pipe take (x+3) min. In one minute the faster pipe filled the cistern= 1/x In 3 1/13= 40/13 min the faster pipe filled the cistern= 40/13 × (1/x) = 40/13x In 3 1/13= 40/13 min the slower pipe filled the cistern= 40/13 × (1/x+3) = 40/13(x+3). ATQ 40/13x + 40/13(x+3) = 1 40/13 [ 1/x + 1/(x+3)] = 1 40 [ (x +3+x) / x(x+3)] =13 40(2x +3) =13 x(x+3)] 80x + 120 = 13x² +39x 13x² +39x -80x -120= 0 13x² - 41x -120= 0 13x² - 65x +24x -120= 0 13x(x -5) + 24(x -5)= 0 (13x +24)(x -5)= 0 (13x +24)= 0 or (x -5)= 0 x =- 24/13 or x = 5 Time cannot be in negative.so, 5 min

? Pranali.A.P ? 5 years, 5 months ago

3 , 1/13 hai

? Pranali.A.P ? 5 years, 5 months ago

Vo 3 1 upon 2 hai

Lucifer?? Morningstar?? 5 years, 5 months ago

Together in ke baad samjh nhi arha

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