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A man saved Rs 16500 in …

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A man saved Rs 16500 in 10 years. In each year after the first year he saved Rs 100 more than he did in the preceding year. How much did he save in the first year?

    • Posted by Lucifer?? Morningstar?? 5 years, 5 months ago

    CBSE > Class 10 > Mathematics
    • 2 answers

    Arun Patel 5 years, 5 months ago

    sum of AP = n{ 2a + (n-1)d}/2 = 10{2a + (10 - 1)100}/2 so 16500 = 5 {2a + 900} 3300 = 2a + 900 3300 -900 =2a 2400 =2a 2400/2 =a a = 1200 so he saved Rs 1200 in the first year 1650 - 900 = 2a 7

    0Thank You

    ? Pranali.A.P ? 5 years, 5 months ago

    Second installment= a + 100 Third installment = a+100+100 The sum of his saving every years Sn=n/2[2a+(n-1)d] a=first term for the given A.P d=common difference of the given A.P n= number of terms n=10 S10 =10/2[2(a)+(9)(100)] 16500=5[2a+(9)(100)] 16500 =10a=4500 16500-4500=10a 12000=10a a=12000/10 Solving for a 10a=12000 a=12000/10 a=1200

    0Thank You

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