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A number when divided successively by …

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A number when divided successively by 4 , 5 and 6 leaves remainders 2,3 and 4 respectively the least number is
  • 1 answers

Yogita Ingle 4 years, 10 months ago

Let p be the number.

Suppose,

p÷4=q, remainder=2

q÷5=r, remainder=3

r÷6=s, remainder=4

Then,

r=6s+4

q=5r+3=5(6s+4)+3=30s+23

p=4q+2=4(30s+23)+2=120s+94

Let us now assume that the remainder s=1. Then we have:

p=(120×1)+94=214

Hence, the number is 214.

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