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The sum of n terms of …

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The sum of n terms of two AP are in the ratio (7n–5):(5n–17) show that their term are equal.

    • Posted by Lucifer?? Morningstar?? 5 years, 5 months ago

    CBSE > Class 10 > Mathematics
    • 5 answers

    Seraj Ali ??? #Srhmk 5 years, 5 months ago

    Tum mera name kaise jante ho

    0Thank You

    Seraj Ali ??? #Srhmk 5 years, 5 months ago

    Tum dono mai se Lucifer kon hai

    0Thank You

    Lucifer ? Morningstar? 5 years, 5 months ago

    Nothing

    1Thank You

    Yogita Ingle 5 years, 5 months ago

    Let a , d and A , D be the first term and the common ratio of the first and the second AP respectively.

    So [(n/2){2a+(n-1)d}]/[(n/2){2A+(n-1)D}]

    =(7n-5)/(5n+17)={7(n-1)+2}/{5(n-1)+22}

    So {2a+(n-1)d}/{2A+(n-1)D}

    ={2+7(n-1)}/{22+5(n-1)} =>

    a=1, d=7, A =11, D = 5

    6th term of 1st AP =a+5d=1+5×7=36

    6th term of 2nd AP=A+5D=11+5×5=36

    1Thank You

    Anushka ?? 5 years, 5 months ago

    U didn't answer me what happened

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