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A 4kg banana bunch is suspended …

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A 4kg banana bunch is suspended motionless from a spring balance whose force constant is k=300N/m. The length upto which the spring will be stretched. # iit jee advanced
  • 5 answers

Aakash Kumar 5 years, 3 months ago

I can solve your other questions of physics

Aakash Kumar 5 years, 3 months ago

Yes

Khushi....? ??‍? 5 years, 3 months ago

Yes Akash now your answer matched both thanku so much can you solve my other questions too....

Aakash Kumar 5 years, 3 months ago

Does the answer matches, reply pls

Aakash Kumar 5 years, 3 months ago

kx=Mg so x=mg/k=4×10/300 m=2/15 m 40/3 cm =13.33cm
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