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A current has a fuse of 5 A . What is maximum number of 100 w, 220 v bulbs that can safely used in a circuit

Posted by Arpita Kakkar 5 years, 6 months ago

CBSE > Class 10 > Science

1 answers

Ranbeer Boparai 5 years, 6 months ago

Rating of the fuse=5 A, Now since each bulb has a power of 100W and potential difference is 220V, so the electricity supply required for each bulb=I=P/V=100/220=5/11A. Let the number of the bulbs required be 'n' A.T.Q 5/11*n=5 Therefore, n=11, so the number of bulbs required=11

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CBSE > Class 10 > Science