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calculate molality of 2.5 g of …

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calculate molality of 2.5 g of ethanoic acid(CH3COOH) in 75 g of benzene.
  • 2 answers

Anshul Pandey 5 years, 6 months ago

0.55

Priti Dubey 5 years, 6 months ago

given mass = 2.5 (ch3cooh) molar mass of ethanoic acid = 60 no. of moles of ch3cooh = 2.5/60 =0.04 moles molility= 0.04/75×1000 = 8/15 = 0.53m
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