Ifp(E)=0.05,what is the probabilityof'notE'?

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Yogita Ingle 5 years, 5 months ago
We know,
P(E) + P( not E) = 1
here, P(E) = 0.05
0.05 + P(not E) = 1
P(not E) = 1 -0.05 = 0.95
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