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Sum of the areas of two …

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Sum of the areas of two square is 400m^. If the difference between their perimeter is 16 .find the sides of each square

Posted by Beepanshu Kumar 5 years, 5 months ago

CBSE > Class 10 > Mathematics

4 answers

Lucifer ? Morningstar? 5 years, 5 months ago

From eq(१) put the value of a1 in a1a2=192 then we get, (a2–4)a2=192 => (a2)²-4a2=192 | | then factorise it and get ur answer

Lucifer ? Morningstar? 5 years, 5 months ago

(a2-a1)²+2a1a2=400। => 2a1a2=384 => a1a2=192

Lucifer ? Morningstar? 5 years, 5 months ago

(a1)²+(a2)²=400 | | next, 4à2–4a1=16 => à2–a1=4 ....(१)

Lucifer ? Morningstar? 5 years, 5 months ago

Let the side of square be a1 and a2 [where a1<a2] Then, (a1)²+(a2)²=400. A/q 4a2-4a1=16. | | a2–a1=4

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