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If two charge particles of charge q1and q2 placed at 'r ' separation having force 80n . Find the value of new electric force if distance becomes half?

Posted by Annu Kumari 5 years, 6 months ago

CBSE > Class 10 > Science

2 answers

Study Lover ?‍? ?‍? 5 years, 6 months ago

F=k×q1×q2/r^2=80(given).--------------------(1) New F'=(kq1q2)÷(r/2^2.) F'=(kq1q2×4)r^2 F'=80×4=320. (using (1))

1Thank You

Lucifer?? Morningstar?? 5 years, 6 months ago

160n

2Thank You

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