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Express the trignometric ratio sinA , …

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Express the trignometric ratio sinA , secA, and tanA in terms of cotA

Posted by Ashok Singh 5 years, 5 months ago

CBSE > Class 10 > Mathematics

2 answers

Study Lover ?‍? ?‍? 5 years, 5 months ago

1.TanA=1/cotA 2. sinA÷cosA=TanA SinA×1/cosA=1/cotA SinA×1/sin(90-A)=1/cotA SinA/sin(90-A)=1/cotA 3. secA=1/cosA SecA=1/cotA×sinA [cosA/sinA=cotA] SecA×sinA=1/cotA Sec×cos(90-A)=1/cotA SecA×1/sec(90-A)=1/cotA SecA/sec(90-A)=1/cotA

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Mithali Pattanaik?? 5 years, 5 months ago

[ i ] sinA in terms of cotA : sinA = 1 / cosecA We know that: cosec²A = 1 + cot²A sinA = 1 / √1 + cot²A [ ii ] secA in terms of cotA : We know that: 1 + tan²A = sec²A secA = 1 + tan²A secA = 1 + 1 / cot²A secA = √(cot²A + 1 ) /cotA [ iii ] tanA in terms of cotA : tanA = 1 / cotA I hope it will help you?

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