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The sum of three numbers in …

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The sum of three numbers in A P is 24 and their product is 440 finde the numbers
  • 4 answers

Deepa Kumari 5 years, 5 months ago

a+ d +a+a-d = 24. 3a=24 a= 8 (a+d)a(a-d)=440 a(a^2-d^2)=440 8(8^2-d^2) =440 64- d^2=55 d^2=9 d= 3 Required no.= 11, 8 and 5.

Aryan Pachouri 5 years, 5 months ago

5,8,11 or 11,8,5

Lucifer ? Morningstar? 5 years, 5 months ago

Next, (a+d)a(a–d)=440 => (64–d²)8=440 => d²=9 d=3.

Lucifer ? Morningstar? 5 years, 5 months ago

Let the no. be (a+d),a,(a–d)। । A/q a+d+a+(a–d)=24 => 3a=24 => a=8.
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