The base of an isoceles triangle …
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Posted by Devanshi Tiwari 4 years, 4 months ago
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Yogita Ingle 4 years, 4 months ago
Altitude in an isosceles triangle is = h
{tex}Area = \frac{1}{2}\ h\ a\ =\ 60\ cm^2 \\ \\ h\ =\ 2\ *\ \frac{60}{24} = 5 cm \\ \\ b^2 = \frac{a}{2}^2 + h^2 = 12^2 + 5^2 = 169 \\ \\ b = c = 13 cm \\ \\ Perimeter = a+b+c = 24+13+13 = 50 cm{/tex}
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