One of the diagnol of rhhombus …
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Yogita Ingle 4 years, 4 months ago
Let construct a rhombus with diagonal of 16 cm and d2
Area = 1/2 × d1 × d2
96 cm2 = 1/2 × 16 cm × d2
96 cm2 = 8 cm × d2
96 cm2 / 8 cm = d2
12 cm = d2
Now half the diagonals to make a small triangle AOB
16/2 = 8 cm
12/2 = 6 cm
{tex}{h}^{2} = {b}^{2} + {p}^{2} \\ {h}^{2} = {8}^{2} + {6}^{2} \\ {h}^{2} = 64 + 36 \\ {h}^{2} = 100 \: {cm}^{2} \\ h = \sqrt{100} \\ h = 10 \: cm{/tex}
Hence side are length of 10 cm
Perimeter = 4 (10) = 40 cm
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