One of the diagnol of rhhombus …

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One of the diagnol of rhhombus is 12cm and area is 96cm.sq find perimeter

Posted by Tarleen Kaur 4 years, 4 months ago

CBSE > Class 09 > Mathematics

1 answers

Yogita Ingle 4 years, 4 months ago

Let construct a rhombus with diagonal of 16 cm and d2

Area = 1/2 × d₁ × d₂

96 cm² = 1/2 × 16 cm × d₂

96 cm² = 8 cm × d₂

96 cm² / 8 cm = d₂

12 cm = d₂

Now half the diagonals to make a small triangle AOB

16/2 = 8 cm
12/2 = 6 cm

{tex}{h}^{2} = {b}^{2} + {p}^{2} \\ {h}^{2} = {8}^{2} + {6}^{2} \\ {h}^{2} = 64 + 36 \\ {h}^{2} = 100 \: {cm}^{2} \\ h = \sqrt{100} \\ h = 10 \: cm{/tex}

Hence side are length of 10 cm
Perimeter = 4 (10) = 40 cm

0Thank You

ANSWER

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CBSE > Class 09 > Mathematics