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Equation of a circle is x^2+y^2-2x+4y=0. …

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Equation of a circle is x^2+y^2-2x+4y=0. Find equation of one of its diameter.

Posted by Ayushi Patel 5 years, 6 months ago

CBSE > Class 12 > Applied Maths

5 answers

Lokendra Tomar 5 years ago

Aap kha se ho

Ravindra Bijarniya 5 years ago

Oo bhai kaha se laya hai

Satyam Mishra 5 years ago

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Yash Sharma 5 years ago

??oo bhai kya hai ye

Dhruv Sarkar 5 years, 5 months ago

The equation can be written as (x-1)^2 + (y+2)^2 = 5. —(1). => center of the circle is at O(1,-2). Now solve for eq(1) and y=0 so that we get the point(s) of intersection of the circle with the x-axis.The points will be A(3,0) and B(-1,0). The equation of the line OA will then be (by using two point form), x-y-3=0, which is the equation of one of the diameters,

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