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a toy gun with a spring …

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a toy gun with a spring which is compressed by 3 cm is used to project s stone of mass 50g to a height of 10m.

a. What is the potential energy of the spring?

b. How much it should be compressed to throw the stone to a height 5m?

c. Find out the physical constant associated with the spring? (g =10)

Posted by Athira Shaji 9 years ago

CBSE > Class 11 > Physics

1 answers

Bindu Agarwal 9 years ago

$(a) S i n c e t h e s p r i n g p o t e n t i a l e n e r g y i s j u s t e n o u g h t o p r o j e c t t h e s t o n e 10 m h i g h \Rightarrow P . E . o f s t o n e a t 10 m h e i g h t = P . E . o f t h e s p r i n g = m g h = (50 / 1000) * 10 * 10 = 5 J (b) S i n c e 0.5 * k * x^{2} = m * g * (10) (w h e n x = 3 c m) N o w 0.5 * k * y^{2} = m * g * (5) \Rightarrow y = x / \sqrt{2} \Rightarrow y = 3 / \sqrt{2} H e n c e i t s h o u l d b e c o m p r e s s e d b y y c m t o t h r o w i t t o a h e i g h t o f 5 m . (c) S i n c e 0.5 * k * (0.03)^{2} = 5 \Rightarrow k = 11111.11$

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