No products in the cart.

Find the value of p and …

CBSE, JEE, NEET, CUET

CBSE, JEE, NEET, CUET

Question Bank, Mock Tests, Exam Papers

NCERT Solutions, Sample Papers, Notes, Videos

Find the value of p and q so that x^4+px^3+2x^2-3x+q is divisible by (x^2-1)
  • 1 answers

Srushti Khadtare 4 years, 5 months ago

Value of p=3, value of q =-3 Step-by-Step explanation: Given polynomial, Factors of p(x) are x+1 & x-1 According to factor theorem which states that a linear polynomial of form x-a is factor of polynomial p(x) if p(a) = 0 So, we get p(1)= 0 1^4+p(1)^3+2(1)^2-3(1)+q = 0 1+p+2-3+q=0 P+q=0................(1) P(-1)=0 (-1)^4+p(-1)^3+2(-1)^2-(3-1)+q=0 1-p+2+3+q=0 q-p=-6................(2) Add equation (1)&(2)we get 2q=-6 =>q=-3 Put this in equation (1) p+(-3)=0 =>p=3 Therefore, value of p =3 and q=-3.
http://mycbseguide.com/examin8/

Related Questions

What is 38747484±393884747
  • 0 answers
X³-12x²+39x-28
  • 0 answers
Ch-1 introduction
  • 0 answers
3√2×4√2×12√32
  • 0 answers
2x+5y
  • 0 answers

myCBSEguide App

myCBSEguide

Trusted by 1 Crore+ Students

Test Generator

Test Generator

Create papers online. It's FREE.

CUET Mock Tests

CUET Mock Tests

75,000+ questions to practice only on myCBSEguide app

Download myCBSEguide App