Find the roots of the quadratic …

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Gaurav Seth 5 years, 6 months ago
3
-2√6x+2=0
-√6x-√6x+2=0
*√3
-√3x*√2x-√3x*√2x+√2*√2=0
3
√3
√3x(√3x-√2)-√2(√3x-√2)=0
(√3x-√2)(√3x-√2)=0
x=√2/√3
Therefore the equation has two equal roots; √2/√3
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