Find the zeroes of the polynomials …

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Gaurav Seth 5 years, 6 months ago
P(X) = 4✓3X²+5X-2✓3
=> 4✓3X² +8X-3X-2✓3
=> 4X(✓3X+2) -✓3(✓3X+2)
=> (✓3X+2)(4X-✓3) = 0
=> (✓3X +2)= 0 OR (4X-✓3) = 0
=> X = -2/✓3 OR X = ✓3/4
-2/✓3 and ✓3/4 are the two zeros of the given polynomial.
Let Alpha = -2/✓3 and beta = ✓3/4
Relationship between the zeros and Coefficient.
Sum of zeros = (Alpha + Beta) = -2/✓3 + ✓3/4 = -8+3/4✓3 = -5/4✓3 = - ( Coefficient of X/Coefficient of X²)
And,
Product of zeros = (Alpha × Beta) = -2/✓3 × ✓3/4 = -2✓3/4✓3 = Constant term/Coefficient of X².
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