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The sum of the two digit numbers is 8 and the difference between the number and that formed by reversing thr digits is 18 .Find the number

Posted by Bhavya Gupta 5 years, 6 months ago

CBSE > Class 10 > Mathematics

1 answers

Yogita Ingle 5 years, 6 months ago

Let the unit place digit be x
And tens place digit be y
No. Formed by x and y = 10y+x (I have multiplied y by ten because it is on tens place)
Now, no. Obtained by reversing digits = 10x+y
Here sum of digits = 8 (I)
And difference on reversing digits is 18
A/q
(10y+x) - (10x+y) = 18
Or, 10y+x-10x-y= 18
Or, 9y-9x = 18
Or, 9(y-x) = 18
Or y-x = 18/9= 2(ii)
On adding both the given equation
Now, y+x = 8
y-x = 2
------------------
2y. = 10
Or, y =5
Now putting the value of y in equation 1st
y+x=8
5+x=8
Or, x= 3
Now the formed no. = 53

1Thank You

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