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What are zeroes of the polynomial X2 - 4

Posted by Ishant Sehrawat 5 years, 7 months ago

CBSE > Class 09 > Mathematics

1 answers

Yogita Ingle 5 years, 7 months ago

P(x) = x² - 4,

= (x)² - (2)²

=(x-2) & (x+2)

Zeroes are 2 & -2 since p(2)= p(-2)=0. Once we find zeroes, we can easily find the factors. For this equation x²-4=0, factors are (x-2) & (x+2) using remainder theorem.

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