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(3x–2y)³÷(3x+2y)²

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(3x–2y)³÷(3x+2y)²

Posted by Riya Singh 5 years, 7 months ago

CBSE > Class 09 > Mathematics

1 answers

Yogita Ingle 5 years, 7 months ago

(3x–2y)³÷(3x+2y)² =

{tex}(3x - 2y)^3 =(3x-2y-3x-2y)[(3x-2y)^2 {/tex}

3x–2y)³÷(3x+2y)² ={tex}(3x-2y-3x-2y)[(3x-2y)^{/tex}2 ÷(3x+2y)²

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