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If A(1,2),B(-3,2)and C(3,-2) be the vertices …

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If A(1,2),B(-3,2)and C(3,-2) be the vertices of the triangle ABC, show that tanA=2.
  • 1 answers

Yogita Ingle 5 years, 7 months ago

The vertices of the triangle ΔABC are A (1, 2), B (- 3, 2) and C (3, - 2). The sides of the triangle are AB, BC, CA and we have to find the tangent ratio of the angle A.

The slope of the line AB is

m₁ = (2 - 2) / (- 3 - 1)

= 0 and

that of the line CA is

m₂ = (2 + 2) / (1 - 3)

= - 2

Then the angle A is determined from

tanA = (m₁ - m₂) / (1 + m₁m₂)

= (0 + 2) / (1 + 0)

= 2

Hence tanA = 2

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