If A(1,2),B(-3,2)and C(3,-2) be the vertices …
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Yogita Ingle 5 years, 8 months ago
The vertices of the triangle ΔABC are A (1, 2), B (- 3, 2) and C (3, - 2). The sides of the triangle are AB, BC, CA and we have to find the tangent ratio of the angle A.
The slope of the line AB is
m₁ = (2 - 2) / (- 3 - 1)
= 0 and
that of the line CA is
m₂ = (2 + 2) / (1 - 3)
= - 2
Then the angle A is determined from
tanA = (m₁ - m₂) / (1 + m₁m₂)
= (0 + 2) / (1 + 0)
= 2
Hence tanA = 2
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