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Application of gauss' law

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Application of gauss' law
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Yogita Ingle 5 years, 5 months ago

1. In the case of a charged ring of radius R on its axis at a distance x from the centre of the ring. E = <latex>14π0qx(R2+x2)3/2\frac{1}{4\pi {{\in }_{0}}}\frac{qx}{{{\left( {{R}^{2}}+{{x}^{2}} \right)}^{3/2}}}4π∈0​1​(R2+x2)3/2qx​</latex>. At the centre, x = 0 and E = 0.

2. In case of an infinite line of charge, at a distance ‘r’. E = (1/4 × πrε0) (2π/r) = λ/2πrε0. Where λ is the linear charge density.

3. The intensity of the electric field near a plane sheet of charge is E = σ/2ε0K where σ = surface charge density.

4. The intensity of the electric field near a plane charged conductor E = σ/Kε0 in a medium of dielectric constant K. If the dielectric medium is air, then Eair = σ/ε0.

5. The field between two parallel plates of a condenser is E = σ/ε0, where σ is the surface charge density.

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