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Calculate the boiling point of one …

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Calculate the boiling point of one molar solution of solute the density of solution is 1.04g ml-1 and Kb is 0.52k kg mol-1

Posted by Pallavi Mandavi 5 years, 11 months ago

CBSE > Class 12 > Chemistry

2 answers

Kaustubh Dutt Rai 5 years, 11 months ago

If there is KCL in question, Then, Molar mass of KCl = 39 + 35.5 = 74.35 g mol-1 As KCl dissociates completely, number of ions produced are 2. Therefore, van't Hoff factor, i = 2 Mass of KCl solution = 1000 x 1.04 = 1040 g Mass of solvent = 1040 - 74.5 = 965.5 g = 0.9655 kg Molality of the solution (m): m=no. Of moles of solute/mass of solvent in kg. =1/0.955 = 1.035m Now, Tb =i×Kb×m=2×0.52×1.035 =1.078°c Therefore, Boiling point of solution =100+1.078=101.078°c

Kaustubh Dutt Rai 5 years, 11 months ago

Mention the name of solute in this problem.

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