Find the value of cot 10 …
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Posted by Raj Singh 6 years, 6 months ago
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Sia ? 6 years, 6 months ago
= cot 10° cot 30° cot 80°
= cot (90° - 80°) cot 30° cot 80°{tex}[\because cot(90^o-\theta)=tan\theta]{/tex}
{tex}=tan80^o. cot30^o{/tex}.{tex}\frac { 1 } { \tan 80 ^ { \circ } }{/tex}{tex}[\because cot\theta=\frac{1}{tan\theta}]{/tex}
{tex}=cot30^o{/tex} {tex}=\sqrt{3}{/tex}
Therefore, {tex}cot10^o cot30^o cot80^o=\sqrt{3}{/tex}
{tex}{/tex}
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