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If A, B and C are …

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If A, B and C are interior angles of a triangle ABC, then show that sin [ B + C / 2 ] = cos A/2.

Posted by Saipreet . 5 years, 7 months ago

CBSE > Class 10 > Mathematics

5 answers

Lucifer ? Morningstar? 5 years, 7 months ago

Then proved that sin[B+C/2]=cosA/2

Lucifer ? Morningstar? 5 years, 7 months ago

And sin(90°-A/2)= CosA/2

Lucifer ? Morningstar? 5 years, 7 months ago

Dividing both side by 2 ||. B+C/2=90°-A/2

Lucifer ? Morningstar? 5 years, 7 months ago

We know that,A+B+C=180° ||. B+C=180°-A

Saipreet . 5 years, 7 months ago

???

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