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An attracting force of 5N is …

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An attracting force of 5N is acting btw two charges of +2uc and -2uc placed at some distance apart.if charges are mutualy touched and placed again at the same distance what will be the new force

Posted by Nimisha Nirdosh 5 years, 5 months ago

CBSE > Class 12 > Physics

1 answers

Rhea Sharma 5 years, 5 months ago

F= kq1q2/r^2 Therefore, 5= 9*10^9(2*10^-6)C(2*10^-6)C/r^2 r^2 = 36*10^-3/5 r = √36*10^-3/5 r= 6*10^-1√10/√5 r= 6√10/10√5 r = 6√5√2/10√5 r= 6√2/10 = 3√2/5 m Force will remain same that is 5N and will be attractive

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