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For what value of k do the equation 3x+2ky_2=0 and 2x+5y+1 =0 are parallel

Posted by Manpreet Kaur 5 years, 7 months ago

CBSE > Class 10 > Mathematics

1 answers

Yogita Ingle 5 years, 7 months ago

3x + 2ky = 2
=> 2ky = -3x + 2
=>y = (-3/2k)x + (1/k)
°slope(m₁)=(-3/2k)
also,
2x + 5y + 1 = 0
=> 5y = -2x - 1
=> y = (-2/5)x - (1/5)
°slope(m₂) = (-2/5)
since, lines are parallel
therefore, m₁=m₂
that is, (-3/2k) = (-2/5)
this applies: on further solving:
{k = 15/4}

3Thank You

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