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Side of a triangle are in the ratio 11:19:24 and it's perimeter 540cm find the area of the triangle

    • Posted by Sontoshidevi Rajput 4 years, 11 months ago

    CBSE > Class 09 > Mathematics
    • 2 answers

    Arpit Raj 4 years, 11 months ago

    Let the ratio be 11x,19x,24x 11x +19x+24x =540 54x=540 x=10 11x= 11×10=110 19x=19×10=190 24x=24×10=240 Semi perimeter=a+b+c/2 (scalence triangle) 110+190+240/2=570/2=270 Area of scalence triangle = √s(s-a)(s-b)(s-c). (Heronce formula) (s-a)=270-110=160cm (s-b)=270-190=60cm (s-c)=270-240=30cm √270×160×60×30 √3×3×3×10×2×2×2×2×10×3×2×10×3×10 √(3×3×10×2×2×10)^2×6 9×100×4×6 24×9×100 21600cm^2 Therefore the area of triangle is 21600cm^2

    2Thank You

    Yogita Ingle 4 years, 11 months ago

    Let the ratio be 11x 19x and 24x

    11x +19x+24x =540

    54x =540 .: x = 540/54

    Hence x=10

    11x =11×10=110 19x= 19×10 =190

    24x=24 × 10 =240

    2Thank You

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