A solid toy is in the …

Given height of cone = h = 10 cm
Radius of base r = 7 cm
Volume of cone V1 = 1/3 π r² h
                              = 1/3 π x 49 x 10
                             = 490 π / 3
Volume of hemisphere V2 = 2/3 π r³
                                          = 2/3 π x 7 x 7 x 7
                                          = 686 π / 3
So V₁ + V₂ = 490 π / 3 + 686 π / 3
                   = 1176 π / 3
                  = 1232 cm³
We know that curved surface area of cone = π r l
                                        {tex}= 22/7 x 7 x 12.2 (l = √r^2 + h^2 = √7^2 + 10^2 = √149){/tex}
                                                          = 268.4  
Curved surface area of hemisphere = 2 π r²  
                                                        = 2 x 22/7 x 7  x 7
                                                       = 44 x 7
                                                      = 308  
So total area to cover the sheet will be 268.4 + 308 = 576.4 cm²