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Side of a triangle are in the ratio of 12 : 17 : 25 and its perimeter is 540 cm. Find its area

    • Posted by Akash Verma 4 years, 7 months ago

    CBSE > Class 09 > Mathematics
    • 1 answers

    Aditya Srivastava 4 years, 7 months ago

    Hi , Perimeter of Triangle = a+b+c /2 Perimeter = 540 cm Let the side be x 12x , 17x , 25x ATQ , 12x +17x +25x = 540 54x = 540 x = 10 Sides 12x = 120 17x = 170 25x = 250 Now The Perimeter = 540 /2 = 270 cm Area =square root of S(s-a)(s-b)(s-c) 270 (270 - 120)(270- 170)(270-250) 270 × 150 × 100 × 20 √40500×100×20 = ​√81000000 = 9000 cm ^2 ​​

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