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Vapour pressure of pure water is …

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Vapour pressure of pure water is 80 mmHg at some temperature. Find vapour pressure of solution containing 15 gram urea dissolve in 90 gram of water

Posted by Jannat Khan 5 years, 9 months ago

CBSE > Class 12 > Chemistry

6 answers

Ayush Kumar 5 years, 9 months ago

Given V.P of pure water= 80mm Hg Mass of water= 90 grams Mass of urea = 15 grams Soln- From Raoult's law V.P of soln= V.P of pure liquid x Xsolvent = V.Pliquid x moles of solvent/ moles of solute + moles of solvent = 80 x 5/0.25 + 5 = 80 x 0.95 = 76mm Hg Hence, the V.P of soln. is 76mm Hg I hope its Helpful... ?

Jannat Khan 5 years, 9 months ago

Pta ho toh bta dijiye

Jannat Khan 5 years, 9 months ago

M is saal 12th m aayi hu mujhe 1 question m prb aa rhi thi

Jannat Khan 5 years, 9 months ago

Pr abhi aayi hu 12th m bahiya

Lalit Dubey 5 years, 9 months ago

Maths padho ab

Lalit Dubey 5 years, 9 months ago

Chemistry ka paper ho gya h tab bhi chem leke bethi ho

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